Example 1. Which of the following is an irrational number?
(i) 3.14
(ii) 3.
14
(iii) 3.14141414...
(iv) 3.14114111411114...
Solution
The correct answer is (iv) 3.14114111411114... as it is a nonterminating, nonrepeating number
Example 2. Which of the following is an irrational number?
(i) $\sqrt{\frac{9}{16}}$
(ii) $\sqrt{49}$
(iii) $\frac{\sqrt{63}}{\sqrt{7}}$
(iv) $\sqrt{7}$
Solution
The correct answer is (iv) $\sqrt{7}$ as it is a nonterminating, nonrepeating number
Example 3. Which of the following is a rational number?
(i) 0.10100100010000...
(ii) $\sqrt{5}$
(iii) $\frac{\sqrt{63}}{\sqrt{9}}$
(iv) $\sqrt{361}$
Solution
The correct answer is (iv) $\sqrt{361}$ as it is a perfect square. $19^2 = 361$
Example 4. Find an irrational number between $\frac{1}{5}$ and $\frac{2}{5}$
Solution
We have
$\frac{1}{5} = 0.2$ and
$\frac{2}{5} = 0.4$ and
To find an irrational number between $0.2$ and $0.4$, we find a number which is
non-terminating and non-repeating. There are infinite numbers which satisfy this criteria.
One such number is 0.31311311131111...
Example 5. Rationalise the denominator $\frac{1}{2 + \sqrt{3}}$
Solution
To rationalise the denominator, we multiply the numerator and denominator by the conjugate
of the denominator.
The conjugate of $(2 + \sqrt{3})$ is $(2 - \sqrt{3})$
Hence we have
$\begin{align*}
& \frac{1}{2 + \sqrt{3}} \\
& = \frac{1}{2 + \sqrt{3}} * \frac{2 - \sqrt{3}}{2 - \sqrt{3}} \\
& = \frac{2 - \sqrt{3}}{2^2 - \sqrt{3}^2} \\
& = \frac{2 - \sqrt{3}}{4 - 3} \\
& = 2 - \sqrt{3}
\end{align*}
$