A die is thrown once. Find the probability of getting a prime number.

The correct answer is $\frac{1}{2}$

A prime number (or a prime) is a natural number greater than 1 that has no positive divisors other than 1 and itself.
Among the numbers 1 through 6, the numbers 2, 3, and 5 are the prime numbers, while 1, 4, and 6 are not prime.
Let E be the event of getting a prime number on throw of a die.
∴ The number of outcomes favourable to E = 3 i.e. when either 2 or 3 or 5 appear on the die.
Total possible outcomes = 6
∴ Probability of getting a prime number = P(E) = $\frac{3}{6}$ = $\frac{1}{2}$