Find $\dfrac{dy}{dx}$, if $2x + 3y = sin x$

The correct answer is $\dfrac{cos x - 2}{3}$

$2x + 3y = sin x$

Differentiating with respect to $x$,

$2 + 3 \dfrac{dy}{dx} = cos x$

∴ $\dfrac{dy}{dx} = \dfrac{cos x - 2}{3}$