Find the derivative of $f(x)$ = $sin(ln(x))$

The correct answer is $\dfrac{cos(ln(x))}{x}$

We have a composition of functions here.

The outside function is $g(x)= sin(x)$
and the inside function is $h(x)= ln(x)$

Using the chain rule, $f'(x) = cos(lx(x)) \dfrac{1}{x}$ = $\dfrac{cos(ln(x))}{x}$