Default
Question
Find the derivative of $f(x)$ = $\sqrt{x}$
Solution
The correct answer is $\dfrac{1}{2}x^{-\frac{1}{2}}$
Explanation
$f(x)$ = $\sqrt{x}$ = $x^\dfrac{1}{2} $
$f′(x)$ = $ \dfrac{1}{2}x^{(\frac{1}{2} - 1)}$ = $\dfrac{1}{2}x^{-\frac{1}{2}}$
3e4ce61f-2f27-11ed-aec7-5405dbb1cb03