Find the derivative of $\dfrac{sin x}{x}$

The correct answer is $\dfrac{x cos x - sin x}{x^2}$

Using the Quotient Rule,
$\dfrac{dy}{dx}$ = $\dfrac{v \dfrac{du}{dx} - u \dfrac{dv}{dx}}{v^2}$

$\dfrac{sin x}{x}$ = $\dfrac{x D(sin x) - sinx D(x)}{x^2}$ = $\dfrac{x cos x - sin x}{x^2}$