Find the unit vector in the direction of the vector $\overrightarrow{a}$ = $\hat{i} + \hat{j} + 2\hat{k} $

The correct answer is $\dfrac{1}{\sqrt{6}} (\hat{i} + \hat{j} + 2\hat{k})$

The unit vector in the direction of the vector $\overrightarrow{a}$

$\overrightarrow{a}$ = $\dfrac{\overrightarrow{a}}{|\overrightarrow{a}|}$ = $\dfrac{\hat{i} + \hat{j} + 2\hat{k}}{\sqrt{1 + 1 + 4}}$ = $\dfrac{1}{\sqrt{6}} \hat{i} + \hat{j} + 2\hat{k}$