For $2 \times 2$ matrix $A = [a_{ij}]$ whose elements are given by $a_{ij} = \dfrac{i}{j}$, then A is equal to

The correct answer is $\left[ \begin{matrix}
1 & \phantom{-} \dfrac{1}{2} \\
2 & 1 \\
\end{matrix} \right]$

Given that $a_{ij} = \dfrac{i}{j}$

∴ $a_{11} = \dfrac{1}{1} = 1$,
$a_{12} = \dfrac{1}{2}$,
$a_{21} = \dfrac{2}{1} = 2$ and
$a_{11} = \dfrac{2}{2} = 1$

$A =$ $\left[ \begin{matrix}

1 & \phantom{-} \dfrac{1}{2} \\

2 & 1 \\

\end{matrix} \right]$