If $P(A) = \dfrac{1}{2}$, $P(B) = 0$, then $P(A|B)$ is

The correct answer is not defined

$P(A|B)$ = $\dfrac{P(A \cap B)}{P(B)}$

However, it is given that $P(B) = 0$.


∴ for $P(B) = 0$, value of $P(A|B)$ is not defined.