In a class of 60 students, 25 students play cricket and 20 students play tennis, and 10 students play both the games, then the number of students who play neither is

The correct answer is 25

Given that $n = 60$, $n(C) = 25$, $n(T) = 20$ and $n(C \cap T) = 10$


Now $n(C \cup T) = n(C) + n(T) - n(C \cap T)$ = 25 + 20 - 10 = 35

Therefore, students who play neither of the games = $n - (C \cup T)$ = 60 - 35 = 25