KARNATAKA-2nd-PUC-2023-Mathematics-Sample-Paper
KARNATAKA 2nd PUC 2023 Mathematics Sample Paper
Question 5
Left hand derivative of $f(x) = |x|$ at $x=0$ is
Solution
The correct answer is -1
Explanation
Left hand derivative = $\lim\limits_{h\to 0^{-1}}$ $\dfrac{f(c+h) - f(c)}{h}$
In the above problem,
Left hand derivative = $\lim\limits_{x\to 0^{-1}}$ $\dfrac{f(x) - f(0)}{x-0}$ = $\lim\limits_{x\to 0^{-1}}$ $\dfrac{-x - 0}{x-0}$
= $\lim\limits_{x\to 0^{-1}} -1$ = $-1$
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