sin(60 + θ) - sin(60 - θ) is equal to

The correct answer is sin θ

We know that
sin(A ± B) = sin A cos B ± cos A sin B

∴ sin(60 + θ) - sin(60 - θ)
= sin 60 cos θ + cos 60 sin θ - sin 60 cos θ + cos 60 sin θ
= 2 × cos 60 sin θ
= 2 × $\frac{√1}{2}$ sin θ
= sin θ